What is the derivative of 3/y ?

The derivative of 3/y is -3/(y^2)

What is the first derivative of 3/y ?

The first derivative of 3/y is -3/(y^2)

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derivative of

\frac{3}{y}

- \frac{3}{y ^{2}}

Solution steps

\frac{d}{d y} (\frac{3}{y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 1 \cdot y^{- 1 - 1})

Simplify

3 (- 1 \cdot y^{- 1 - 1}) : - \frac{3}{y ^{2}}

= - \frac{3}{y ^{2}}

e^{p}

\frac{3}{5 ( s - 3 ) ^{2} + 80}

x^{2} + 2 x + 1, 2 x + 5, - 2, 2

\int x^{2} + 4 x + 5 d x