What is the solution for y^{''}-6y^'=4x ?

The solution for y^{''}-6y^'=4x is y=c_{1}e^{6x}+c_{2}-(x^2)/3-x/9

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y^{''}-6y^'=4x

y^{^{''}} - 6 y^{^{'}} = 4 x

y = c_{1} e^{6 x} + c_{2} - \frac{x ^{2}}{3} - \frac{x}{9}

Solution steps

y^{''} (x) - 6 y^{'} (x) = 4 x

Solve linear ODE:

y = c_{1} e^{6 x} + c_{2} - \frac{x ^{2}}{3} - \frac{x}{9}

y = c_{1} e^{6 x} + c_{2} - \frac{x ^{2}}{3} - \frac{x}{9}

\int \frac{24}{( 399 x - 1 ) ( 399 + 1 )} d x

arcsin (u)

\frac{d}{d x} (3 x^{2} + 2 x y - y^{2})

f (x) = (3 - x)^{4} (x + 5)^{3}

\frac{d y}{d t} = y \cdot ln (y)

What is the solution for y^{''}-6y^'=4x ?
The solution for y^{''}-6y^'=4x is y=c_{1}e^{6x}+c_{2}-(x^2)/3-x/9