What is the derivative of 2x^3-e^x ?

The derivative of 2x^3-e^x is 6x^2-e^x

What is the first derivative of 2x^3-e^x ?

The first derivative of 2x^3-e^x is 6x^2-e^x

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\frac{d}{d x} (2 x^{3} - e^{x})

6 x^{2} - e^{x}

Solution steps

\frac{d}{d x} (2 x^{3} - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 6 x^{2} - e^{x}

\int sin^{3} (x) cos^{5} (x) d x

x \to \infty lim (e^{2 x})

\frac{d}{d x} (\frac{2 x}{1 - 2 x})

\int arcsin (6 x) d x

(3, 1), (0, - 2)

What is the derivative of 2x^3-e^x ?
The derivative of 2x^3-e^x is 6x^2-e^x
What is the first derivative of 2x^3-e^x ?
The first derivative of 2x^3-e^x is 6x^2-e^x