What is the derivative of x^3+3x^2-9x+4 ?

The derivative of x^3+3x^2-9x+4 is 3x^2+6x-9

What is the first derivative of x^3+3x^2-9x+4 ?

The first derivative of x^3+3x^2-9x+4 is 3x^2+6x-9

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\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 4)

3 x^{2} + 6 x - 9

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 3 x^{2} + 6 x - 9 + 0

Simplify

= 3 x^{2} + 6 x - 9

x \to 2 lim (k x)

\int 9 - y^{2} d y

sin (x), cos (x), - \frac{π}{18}, \frac{9}{4}

\frac{d}{d x} (b + c (x - a)^{\frac{2}{3}})

x \to - 2 lim (\frac{x ^{2} - 4}{x - 2})

What is the derivative of x^3+3x^2-9x+4 ?
The derivative of x^3+3x^2-9x+4 is 3x^2+6x-9
What is the first derivative of x^3+3x^2-9x+4 ?
The first derivative of x^3+3x^2-9x+4 is 3x^2+6x-9