What is the solution for (dy)/(dx)= 1/(x+y) ?

The solution for (dy)/(dx)= 1/(x+y) is y=-\W((c_{1})/(e^{x+1)})-x-1

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(dy)/(dx)= 1/(x+y)

\frac{d y}{d x} = \frac{1}{x + y}

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

Solution steps

\frac{d y}{d x} = \frac{1}{x + y}

Solve exact ODE:

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

\frac{\partial}{\partial x} (5 x^{2} y - 5 x + 4 y^{3})

\int x^{2} (e^{x}) d x

x \to - 2 lim (\frac{2 x + 2}{x - 1})

\frac{6 x}{1 - tan ( x )}

\int \frac{x - 3}{x + 1} d x

What is the solution for (dy)/(dx)= 1/(x+y) ?
The solution for (dy)/(dx)= 1/(x+y) is y=-\W((c_{1})/(e^{x+1)})-x-1