What is the tangent of f(x)=ln(x^7),(1,0) ?

The tangent of f(x)=ln(x^7),(1,0) is y=7x-7

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tangent of f(x)=ln(x^7),(1,0)

tangent of

f (x) = ln (x^{7}), (1, 0)

y = 7 x - 7

Solution steps

Find the slope of

f (x) = ln (x^{7}) : \frac{df ( x )}{d x} = \frac{7}{x}

Compute the slope of

f (x) = ln (x^{7})

(1, 0) : m = 7

Find the line with slope m=

7

and passing through

(1, 0) : y = 7 x - 7

y = 7 x - 7

\frac{d y}{d x} = \frac{2 x + 5 y}{x}

\frac{d}{d x} (\frac{6}{( x + 1 ) ^{4}})

\frac{d}{d x} (\frac{x ^{2}}{x + 1})

\int \frac{x ^{2} - 1}{x ^{\frac{3}{2}}} d x

What is the tangent of f(x)=ln(x^7),(1,0) ?
The tangent of f(x)=ln(x^7),(1,0) is y=7x-7