What is the derivative of 1+sec^2(x) ?

The derivative of 1+sec^2(x) is 2sec^2(x)tan(x)

What is the first derivative of 1+sec^2(x) ?

The first derivative of 1+sec^2(x) is 2sec^2(x)tan(x)

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\frac{d}{d x} (1 + sec^{2} (x))

2 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (1 + sec^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sec^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sec^{2} (x)) = 2 sec^{2} (x) tan (x)

= 0 + 2 sec^{2} (x) tan (x)

Simplify

= 2 sec^{2} (x) tan (x)

x \to 2 lim (\frac{x - 9}{x - 9 x})

\int_{4}^{7} x^{3} ln (4 x) d x

e^{\frac{7}{u}}

\frac{d x}{d t} = x - 2

\int csc (\frac{3}{4}) x cot (\frac{3}{4}) x d x

What is the derivative of 1+sec^2(x) ?
The derivative of 1+sec^2(x) is 2sec^2(x)tan(x)
What is the first derivative of 1+sec^2(x) ?
The first derivative of 1+sec^2(x) is 2sec^2(x)tan(x)