What is the solution for (dy}{dx}=\frac{2x)/y ?

The solution for (dy}{dx}=\frac{2x)/y is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}

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(dy}{dx}=\frac{2x)/y

\frac{d y}{d x} = \frac{2 x}{y}

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 x}{y}

Solve separable ODE:

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

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y^{^{''}} - \frac{1}{x} y^{^{'}} = 3 x

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\frac{d}{d x} (cos (x + 2))

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What is the solution for (dy}{dx}=\frac{2x)/y ?
The solution for (dy}{dx}=\frac{2x)/y is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}