What is the solution for y^'+2ty=e^{-t^2} ?

The solution for y^'+2ty=e^{-t^2} is y= t/(e^{t^2)}+(c_{1})/(e^{t^2)}

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y^'+2ty=e^{-t^2}

y^{^{'}} + 2 t y = e^{- t^{2}}

y = \frac{t}{e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

Solution steps

y^{'} (t) + 2 t y = e^{- t^{2}}

Solve linear ODE:

y = \frac{t}{e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

y = \frac{t}{e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

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(x + 2)^{\frac{2}{3}}

y = \frac{( x - 2 )}{( x - 3 )}

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What is the solution for y^'+2ty=e^{-t^2} ?
The solution for y^'+2ty=e^{-t^2} is y= t/(e^{t^2)}+(c_{1})/(e^{t^2)}