What is the sum from n=0 to infinity of (-x)^n ?

The sum from n=0 to infinity of (-x)^n is Interval of convergence is-1<x<1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (-x)^n

n = 0 \sum \infty (- x)^{n}

Interval of convergence is - 1 < x < 1

Solution steps

n = 0 \sum \infty (- x)^{n}

Use the Root Test to compute the convergence interval

Interval of convergence is - 1 < x < 1

x \to 0 + lim (\frac{x}{ln ( \frac{1}{x} )})

\frac{\partial}{\partial x} (\frac{y}{2 x})

x \cdot sin (\frac{4}{x})

x^{^{''}} - 8 x^{^{'}} + 16 x = 4 t e^{4 t}

\int - cos (4 x) d x

What is the sum from n=0 to infinity of (-x)^n ?
The sum from n=0 to infinity of (-x)^n is Interval of convergence is-1<x<1