What is the tangent of-2x^2+2x ?

The tangent of-2x^2+2x is y=(-4a_{0}+2)x+2a_{0}^2

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tangent of-2x^2+2x

tangent of

- 2 x^{2} + 2 x

y = (- 4 a_{0} + 2) x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{2} + 2 a_{0})

Find the slope of

y = - 2 x^{2} + 2 x : \frac{d y}{d x} = - 4 x + 2

Compute the slope of

y = - 2 x^{2} + 2 x

x = a_{0} : m = - 4 a_{0} + 2

Find the line with slope m=

- 4 a_{0} + 2

and passing through

(a_{0}, - 2 a_{0}^{2} + 2 a_{0}) : y = (- 4 a_{0} + 2) x + 2 a_{0}^{2}

y = (- 4 a_{0} + 2) x + 2 a_{0}^{2}

x \to 6 lim (21 x + 18)

x \to - \infty lim (- (x))

\int_{y}^{x} cos (e^{t}) d t

\frac{d}{d t} (t + \frac{1}{t})

\int (2 a^{2} x^{2} - b^{3})^{2} d x

What is the tangent of-2x^2+2x ?
The tangent of-2x^2+2x is y=(-4a_{0}+2)x+2a_{0}^2