What is the integral of 1/2 sec^2(x) ?

The integral of 1/2 sec^2(x) is 1/2 tan(x)+C

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integral of 1/2 sec^2(x)

\int \frac{1}{2} sec^{2} (x) d x

\frac{1}{2} tan (x) + C

Solution steps

\int \frac{1}{2} sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= \frac{1}{2} tan (x)

Add a constant to the solution

= \frac{1}{2} tan (x) + C

\frac{\partial}{\partial x} (x^{2} y^{3})

\int \frac{4 x}{x ^{3} + x ^{2} - x - 1} d x

\frac{d}{d x} (- cos (x))

x \to - 1 lim (- x^{2} + 2 x - 9)

- y^{^{'}} + \frac{4 y}{x} = x y^{2}

What is the integral of 1/2 sec^2(x) ?
The integral of 1/2 sec^2(x) is 1/2 tan(x)+C