What is (\partial)/(\partial y)(3y^2+10xy^2) ?

The answer to (\partial)/(\partial y)(3y^2+10xy^2) is 6y+20xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(3y^2+10xy^2)

\frac{\partial}{\partial y} (3 y^{2} + 10 x y^{2})

6 y + 20 x y

Solution steps

\frac{\partial}{\partial y} (3 y^{2} + 10 x y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 y^{2}) + \frac{\partial}{\partial y} (10 x y^{2})

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

\frac{\partial}{\partial y} (10 x y^{2}) = 20 x y

= 6 y + 20 x y

\int \frac{1}{( x + 1 ) ^{2} ( x - 5 )} d x

\frac{d}{d x} (x sin (\frac{2}{x}))

\frac{\partial}{\partial x} (\frac{- y}{2 x ^{2} + y ^{2}})

(x^{2} - 2 x) (2 x - x^{2})

\frac{\partial}{\partial t} (t e^{s t})

What is (\partial)/(\partial y)(3y^2+10xy^2) ?
The answer to (\partial)/(\partial y)(3y^2+10xy^2) is 6y+20xy