What is the derivative of 3/((x^2-5x^2)) ?

The derivative of 3/((x^2-5x^2)) is -(6(2x-5))/((x^2-5x)^3)

What is the first derivative of 3/((x^2-5x^2)) ?

The first derivative of 3/((x^2-5x^2)) is -(6(2x-5))/((x^2-5x)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{3}{( x ^{2} - 5 x ) ^{2}})

- \frac{6 ( 2 x - 5 )}{( x ^{2} - 5 x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{( x ^{2} - 5 x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( x ^{2} - 5 x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{2} - 5 x)^{- 2})

Apply the chain rule:

- \frac{2}{( x ^{2} - 5 x ) ^{3}} \frac{d}{d x} (x^{2} - 5 x)

= - \frac{2}{( x ^{2} - 5 x ) ^{3}} \frac{d}{d x} (x^{2} - 5 x)

\frac{d}{d x} (x^{2} - 5 x) = 2 x - 5

= 3 (- \frac{2}{( x ^{2} - 5 x ) ^{3}} (2 x - 5))

Simplify

3 (- \frac{2}{( x ^{2} - 5 x ) ^{3}} (2 x - 5)) : - \frac{6 ( 2 x - 5 )}{( x ^{2} - 5 x ) ^{3}}

= - \frac{6 ( 2 x - 5 )}{( x ^{2} - 5 x ) ^{3}}

\int \frac{1 - y}{y} d y

\int_{0}^{2.1} π (\frac{21}{10} - x)^{2} d x

\frac{\partial ^{2}}{\partial y ^{2}} (ln (2 + x^{2} y^{2}))

\int tan^{3} (x) sec^{6} (x) d x

\int \frac{1}{9} x^{- \frac{2}{9}} d x

What is the derivative of 3/((x^2-5x^2)) ?
The derivative of 3/((x^2-5x^2)) is -(6(2x-5))/((x^2-5x)^3)
What is the first derivative of 3/((x^2-5x^2)) ?
The first derivative of 3/((x^2-5x^2)) is -(6(2x-5))/((x^2-5x)^3)