What is the solution for y^'=(xy^3)/(25) ?

The solution for y^'=(xy^3)/(25) is y=sqrt(-(25)/(x^2+c_{1))},y=-sqrt(-(25)/(x^2+c_{1))}

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y^'=(xy^3)/(25)

y^{^{'}} = \frac{x y ^{3}}{25}

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = \frac{x y ^{3}}{25}

Solve separable ODE:

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

\frac{\partial}{\partial y} (1 - y^{2})

2 sin (x)

\int \frac{2 x + 1}{e ^{2 x}} d x

\frac{\partial}{\partial x} (e^{x} cos (y) + 2 x - 3 y^{2})

2 + t + \frac{1}{t}

What is the solution for y^'=(xy^3)/(25) ?
The solution for y^'=(xy^3)/(25) is y=sqrt(-(25)/(x^2+c_{1))},y=-sqrt(-(25)/(x^2+c_{1))}