What is the solution for (dy}{dx}=\frac{x^2-x+2)/x+y ?

The solution for (dy}{dx}=\frac{x^2-x+2)/x+y is y=-x+2\Ei(-x)e^x+c_{1}e^x

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(dy}{dx}=\frac{x^2-x+2)/x+y

\frac{d y}{d x} = \frac{x ^{2} - x + 2}{x} + y

y = - x + 2 Ei (- x) e^{x} + c_{1} e^{x}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} - x + 2}{x} + y

Solve linear ODE:

y = - x + 2 Ei (- x) e^{x} + c_{1} e^{x}

y = - x + 2 Ei (- x) e^{x} + c_{1} e^{x}

\int 5 sin (5 x - 3) d x

y = 2 cos (x), y = 5 - 3 cos (x)

sin (x), 5 - x^{2}, [- 2.384677, 2.0252116]

n = 1 \sum \infty \frac{2 ^{n}}{n !}

What is the solution for (dy}{dx}=\frac{x^2-x+2)/x+y ?
The solution for (dy}{dx}=\frac{x^2-x+2)/x+y is y=-x+2\Ei(-x)e^x+c_{1}e^x