What is the derivative of sqrt(x+1)-1 ?

The derivative of sqrt(x+1)-1 is 1/(2sqrt(x+1))

What is the first derivative of sqrt(x+1)-1 ?

The first derivative of sqrt(x+1)-1 is 1/(2sqrt(x+1))

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\frac{d}{d x} (x + 1 - 1)

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (x + 1 - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x + 1) - \frac{d}{d x} (1)

\frac{d}{d x} (x + 1) = \frac{1}{2 x + 1}

\frac{d}{d x} (1) = 0

= \frac{1}{2 x + 1} - 0

Simplify

= \frac{1}{2 x + 1}

e^{3 x c o s (2 x)}

y = - \frac{3}{x} + \frac{2}{x ^{3}}

\int \frac{7 - x ^{2}}{3 x ^{3} + x} d x

\frac{\partial}{\partial y} (x^{5} y z^{2} + 4 yz)

f (x) = x^{2} + x, at a = 5

What is the derivative of sqrt(x+1)-1 ?
The derivative of sqrt(x+1)-1 is 1/(2sqrt(x+1))
What is the first derivative of sqrt(x+1)-1 ?
The first derivative of sqrt(x+1)-1 is 1/(2sqrt(x+1))