What is the derivative of y=4e^{-x}+e^{3x} ?

The derivative of y=4e^{-x}+e^{3x} is -4e^{-x}+e^{3x}*3

What is the first derivative of y=4e^{-x}+e^{3x} ?

The first derivative of y=4e^{-x}+e^{3x} is -4e^{-x}+e^{3x}*3

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derivative of

y = 4 e^{- x} + e^{3 x}

- 4 e^{- x} + e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (4 e^{- x} + e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 e^{- x}) + \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (4 e^{- x}) = - 4 e^{- x}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= - 4 e^{- x} + e^{3 x} \cdot 3

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x - 1)

\frac{d}{d x} (\frac{x - y}{x + y})

\int (x^{2} - 3 x + 5) d x

f (x) = x^{2} + x, at x = 1, at x = 3

\frac{d}{d o} (ln (o))

What is the derivative of y=4e^{-x}+e^{3x} ?
The derivative of y=4e^{-x}+e^{3x} is -4e^{-x}+e^{3x}*3
What is the first derivative of y=4e^{-x}+e^{3x} ?
The first derivative of y=4e^{-x}+e^{3x} is -4e^{-x}+e^{3x}*3