What is the derivative of sqrt(2x) ?

The derivative of sqrt(2x) is 1/(sqrt(2)\sqrt{x)}

What is the first derivative of sqrt(2x) ?

The first derivative of sqrt(2x) is 1/(sqrt(2)\sqrt{x)}

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derivative of

2 x

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (2 x)

Apply the chain rule:

\frac{1}{2 2 x} \frac{d}{d x} (2 x)

= \frac{1}{2 2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{2 2 x} \cdot 2

Simplify

\frac{1}{2 2 x} \cdot 2 : \frac{1}{2 x}

= \frac{1}{2 x}

f (x) = (x^{4} - 4 x) e^{x}

- \frac{8}{x ^{9}}

\int (x^{4} + 2 x - 9) ln (x) d x

\frac{3}{x + 1}

t y^{^{'}} + 2 y = sin (t), y (\frac{π}{2}) = 3

What is the derivative of sqrt(2x) ?
The derivative of sqrt(2x) is 1/(sqrt(2)\sqrt{x)}
What is the first derivative of sqrt(2x) ?
The first derivative of sqrt(2x) is 1/(sqrt(2)\sqrt{x)}