What is the derivative of (3x-4)^3 ?

The derivative of (3x-4)^3 is 9(3x-4)^2

What is the first derivative of (3x-4)^3 ?

The first derivative of (3x-4)^3 is 9(3x-4)^2

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derivative of

(3 x - 4)^{3}

9 (3 x - 4)^{2}

Solution steps

\frac{d}{d x} ((3 x - 4)^{3})

Apply the chain rule:

3 (3 x - 4)^{2} \frac{d}{d x} (3 x - 4)

= 3 (3 x - 4)^{2} \frac{d}{d x} (3 x - 4)

\frac{d}{d x} (3 x - 4) = 3

= 3 (3 x - 4)^{2} \cdot 3

Simplify

= 9 (3 x - 4)^{2}

f (x) = (\frac{3}{4}) x^{\frac{4}{3}}

x \to - 8 lim (e (\frac{3}{( x - 8 )}))

\int \frac{x}{3 x ^{2} - 16} d x

\int 2 cot (x) d x

\frac{d}{d x} (\frac{x y}{( x ^{2} - y ^{2} ) ^{2}})

What is the derivative of (3x-4)^3 ?
The derivative of (3x-4)^3 is 9(3x-4)^2
What is the first derivative of (3x-4)^3 ?
The first derivative of (3x-4)^3 is 9(3x-4)^2