What is the integral from-infinity to 2 of e^{-x} ?

The integral from-infinity to 2 of e^{-x} is diverges

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integral from-infinity to 2 of e^{-x}

\int_{- \infty}^{2} e^{- x} d x

diverges

Solution steps

\int_{- \infty}^{2} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{- \infty}^{2} e^{- x} d x =

diverges

= diverges

\frac{sin ( x )}{1 + cos ( x )}

x \to 2 lim (\frac{x}{x ^{2} - 4})

(5 x^{2} + 4) (3 x - 2)

\int x sin (n x) d x

\frac{d}{d x} (- 2 cot (x))

What is the integral from-infinity to 2 of e^{-x} ?
The integral from-infinity to 2 of e^{-x} is diverges