What is the derivative of (tan(x)/(cos(x)-4)) ?

The derivative of (tan(x)/(cos(x)-4)) is (sec^2(x)(cos(x)-4)+sin(x)tan(x))/((cos(x)-4)^2)

What is the first derivative of (tan(x)/(cos(x)-4)) ?

The first derivative of (tan(x)/(cos(x)-4)) is (sec^2(x)(cos(x)-4)+sin(x)tan(x))/((cos(x)-4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{tan ( x )}{cos ( x ) - 4})

\frac{sec ^{2} ( x ) ( cos ( x ) - 4 ) + sin ( x ) tan ( x )}{( cos ( x ) - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{tan ( x )}{cos ( x ) - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( tan ( x ) ) ( cos ( x ) - 4 ) - \frac{d}{d x} ( cos ( x ) - 4 ) tan ( x )}{( cos ( x ) - 4 ) ^{2}}

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (cos (x) - 4) = - sin (x)

= \frac{sec ^{2} ( x ) ( cos ( x ) - 4 ) - ( - sin ( x ) ) tan ( x )}{( cos ( x ) - 4 ) ^{2}}

Simplify

= \frac{sec ^{2} ( x ) ( cos ( x ) - 4 ) + sin ( x ) tan ( x )}{( cos ( x ) - 4 ) ^{2}}

n = 1 \sum \infty - \frac{5}{2 ^{n - 1}}

x \to \infty lim (3)

\int (x + π) d x

F (s) = \frac{( s + 2 ) ^{2}}{s ^{3}}

y = (x^{2} - 8 x) e^{x}

What is the derivative of (tan(x)/(cos(x)-4)) ?
The derivative of (tan(x)/(cos(x)-4)) is (sec^2(x)(cos(x)-4)+sin(x)tan(x))/((cos(x)-4)^2)
What is the first derivative of (tan(x)/(cos(x)-4)) ?
The first derivative of (tan(x)/(cos(x)-4)) is (sec^2(x)(cos(x)-4)+sin(x)tan(x))/((cos(x)-4)^2)