What is the derivative of tanh(1+e^{2x}) ?

The derivative of tanh(1+e^{2x}) is sech^2(1+e^{2x})*2e^{2x}

What is the first derivative of tanh(1+e^{2x}) ?

The first derivative of tanh(1+e^{2x}) is sech^2(1+e^{2x})*2e^{2x}

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\frac{d}{d x} (tanh (1 + e^{2 x}))

sech^{2} (1 + e^{2 x}) \cdot 2 e^{2 x}

Solution steps

\frac{d}{d x} (tanh (1 + e^{2 x}))

Apply the chain rule:

sech^{2} (1 + e^{2 x}) \frac{d}{d x} (1 + e^{2 x})

= sech^{2} (1 + e^{2 x}) \frac{d}{d x} (1 + e^{2 x})

\frac{d}{d x} (1 + e^{2 x}) = 2 e^{2 x}

= sech^{2} (1 + e^{2 x}) \cdot 2 e^{2 x}

y = \frac{1}{16} (e^{8 x} + e^{- 8 x}), - 4 \leq x \leq 4

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{2} - 1})

\int t cos (8 t) d t

\int - y + 1 d y

\frac{d}{d x} ((4 x^{3} + 5 x) (x - 3) (x + 5))

What is the derivative of tanh(1+e^{2x}) ?
The derivative of tanh(1+e^{2x}) is sech^2(1+e^{2x})*2e^{2x}
What is the first derivative of tanh(1+e^{2x}) ?
The first derivative of tanh(1+e^{2x}) is sech^2(1+e^{2x})*2e^{2x}