What is the derivative of 2xtan(2x+2) ?

The derivative of 2xtan(2x+2) is 2(tan(2x+2)+2xsec^2(2x+2))

What is the first derivative of 2xtan(2x+2) ?

The first derivative of 2xtan(2x+2) is 2(tan(2x+2)+2xsec^2(2x+2))

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\frac{d}{d x} (2 x tan (2 x + 2))

2 (tan (2 x + 2) + 2 x sec^{2} (2 x + 2))

Solution steps

\frac{d}{d x} (2 x tan (2 x + 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x tan (2 x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = tan (2 x + 2)

= 2 (\frac{d x}{d x} tan (2 x + 2) + \frac{d}{d x} (tan (2 x + 2)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (tan (2 x + 2)) = sec^{2} (2 x + 2) \cdot 2

= 2 (1 \cdot tan (2 x + 2) + sec^{2} (2 x + 2) \cdot 2 x)

Simplify

= 2 (tan (2 x + 2) + 2 x sec^{2} (2 x + 2))

y y^{^{'}} + y^{\frac{3}{2}} = 1

\frac{\partial}{\partial x} (ln (x^{7} - y^{6}))

\int 5 tan^{2} (x) sec (x) d x

\int arctan (1) d x

\frac{d}{d x} ((π - x) cos (x))

What is the derivative of 2xtan(2x+2) ?
The derivative of 2xtan(2x+2) is 2(tan(2x+2)+2xsec^2(2x+2))
What is the first derivative of 2xtan(2x+2) ?
The first derivative of 2xtan(2x+2) is 2(tan(2x+2)+2xsec^2(2x+2))