What is the integral of 1/((5x)^2) ?

The integral of 1/((5x)^2) is -1/(25x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((5x)^2)

\int \frac{1}{( 5 x ) ^{2}} d x

- \frac{1}{25 x} + C

Solution steps

\int \frac{1}{( 5 x ) ^{2}} d x

Apply Integration By Parts

: \frac{1}{25 x} - \int - \frac{2}{25 x ^{2}} d x

= \frac{1}{25 x} - \int - \frac{2}{25 x ^{2}} d x

\int - \frac{2}{25 x ^{2}} d x = \frac{2}{25 x}

= \frac{1}{25 x} - \frac{2}{25 x}

Simplify

= - \frac{1}{25 x}

Add a constant to the solution

= - \frac{1}{25 x} + C

\int \frac{ln ( cos ( x ) )}{( cos ( x ) ) ^{2}} d x

\int_{- \infty}^{0} 2^{r} d r

\int (- 9 x + 3)^{4} d x

30 e^{x} + x^{20}

\frac{d}{d x} (5 cos^{3} (x))