What is the derivative of 3x^2-4xy^4-y^3 ?

The derivative of 3x^2-4xy^4-y^3 is 6x-4(y^4+4xy^3(dy)/(dx))-3y^2(dy)/(dx)

What is the first derivative of 3x^2-4xy^4-y^3 ?

The first derivative of 3x^2-4xy^4-y^3 is 6x-4(y^4+4xy^3(dy)/(dx))-3y^2(dy)/(dx)

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\frac{d}{d x} (3 x^{2} - 4 x y^{4} - y^{3})

6 x - 4 (y^{4} + 4 x y^{3} \frac{d y}{d x}) - 3 y^{2} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x y^{4} - y^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x y^{4}) - \frac{d}{d x} (y^{3})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x y^{4}) = 4 (y^{4} + 4 x y^{3} \frac{d y}{d x})

\frac{d}{d x} (y^{3}) = 3 y^{2} \frac{d y}{d x}

= 6 x - 4 (y^{4} + 4 x y^{3} \frac{d y}{d x}) - 3 y^{2} \frac{d y}{d x}

x \to 1 lim (ln (0))

\frac{d}{d x} (\frac{x - 11}{x - 11})

\int \frac{1}{1 + 2 e ^{x} - e ^{- x}} d x

(x^{8} - 2)^{3}

\frac{d}{d t} (0)

What is the derivative of 3x^2-4xy^4-y^3 ?
The derivative of 3x^2-4xy^4-y^3 is 6x-4(y^4+4xy^3(dy)/(dx))-3y^2(dy)/(dx)
What is the first derivative of 3x^2-4xy^4-y^3 ?
The first derivative of 3x^2-4xy^4-y^3 is 6x-4(y^4+4xy^3(dy)/(dx))-3y^2(dy)/(dx)