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Popular >

d/(dt)(t/((t-1)^2))

Solution

\frac{d}{d t} (\frac{t}{( t - 1 ) ^{2}})

Solution

\frac{- 1 - t}{( t - 1 ) ^{3}}

Solution steps

\frac{d}{d t} (\frac{t}{( t - 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d t}{d t} ( t - 1 ) ^{2} - \frac{d}{d t} ( ( t - 1 ) ^{2} ) t}{( ( t - 1 ) ^{2} ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} ((t - 1)^{2}) = 2 (t - 1)

= \frac{1 \cdot ( t - 1 ) ^{2} - 2 ( t - 1 ) t}{( ( t - 1 ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( t - 1 ) ^{2} - 2 ( t - 1 ) t}{( ( t - 1 ) ^{2} ) ^{2}} : \frac{- 1 - t}{( t - 1 ) ^{3}}

= \frac{- 1 - t}{( t - 1 ) ^{3}}

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n = 0 \sum \infty \frac{n}{n ^{3} + 4}

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x^{6} + y^{2} = 2, (1, - 1)

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x y^{^{'}} + 2 y = 3 cos (x)

integral of cos^2(2x)sin^3(2x)

\int cos^{2} (2 x) sin^{3} (2 x) d x

Frequently Asked Questions (FAQ)

What is the d/(dt)(t/((t-1)^2)) ?
The d/(dt)(t/((t-1)^2)) is (-1-t)/((t-1)^3)
What is the first d/(dt)(t/((t-1)^2)) ?
The first d/(dt)(t/((t-1)^2)) is (-1-t)/((t-1)^3)