What is the derivative of (2x-1)/(4x+8) ?

The derivative of (2x-1)/(4x+8) is 5/(4(x+2)^2)

What is the first derivative of (2x-1)/(4x+8) ?

The first derivative of (2x-1)/(4x+8) is 5/(4(x+2)^2)

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derivative of

\frac{2 x - 1}{4 x + 8}

\frac{5}{4 ( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 1}{4 x + 8})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) ( 4 x + 8 ) - \frac{d}{d x} ( 4 x + 8 ) ( 2 x - 1 )}{( 4 x + 8 ) ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (4 x + 8) = 4

= \frac{2 ( 4 x + 8 ) - 4 ( 2 x - 1 )}{( 4 x + 8 ) ^{2}}

Simplify

\frac{2 ( 4 x + 8 ) - 4 ( 2 x - 1 )}{( 4 x + 8 ) ^{2}} : \frac{5}{4 ( x + 2 ) ^{2}}

= \frac{5}{4 ( x + 2 ) ^{2}}

\int \frac{ln ( x ^{4} )}{x} d x

\frac{d}{d x} (\frac{1}{x} e^{x})

\frac{d y}{d x} = a \cdot y

e^{t a n (5 t)}

(e^{f (x)})^{'}

What is the derivative of (2x-1)/(4x+8) ?
The derivative of (2x-1)/(4x+8) is 5/(4(x+2)^2)
What is the first derivative of (2x-1)/(4x+8) ?
The first derivative of (2x-1)/(4x+8) is 5/(4(x+2)^2)