What is the derivative of 3e^{4x} ?

The derivative of 3e^{4x} is 12e^{4x}

What is the first derivative of 3e^{4x} ?

The first derivative of 3e^{4x} is 12e^{4x}

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\frac{d}{d x} (3 e^{4 x})

12 e^{4 x}

Solution steps

\frac{d}{d x} (3 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 3 e^{4 x} \cdot 4

Simplify

= 12 e^{4 x}

2 y^{^{'}} = 3 x y + 1

x \to 1 lim ((x^{2} - 2 x + 1) cos (e^{\frac{1}{x - 1}}))

x \to \infty lim ([2, x])

\int (sin^{2} (x) - cos^{2} (x)) d x

\frac{d ^{5}}{d x ^{5}} (\frac{1}{x})

What is the derivative of 3e^{4x} ?
The derivative of 3e^{4x} is 12e^{4x}
What is the first derivative of 3e^{4x} ?
The first derivative of 3e^{4x} is 12e^{4x}