What is (\partial)/(\partial s)(tcos(s)) ?

The answer to (\partial)/(\partial s)(tcos(s)) is -tsin(s)

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(\partial)/(\partial s)(tcos(s))

\frac{\partial}{\partial s} (t cos (s))

- t sin (s)

Solution steps

\frac{\partial}{\partial s} (t cos (s))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t \frac{\partial}{\partial s} (cos (s))

Apply the common derivative:

\frac{\partial}{\partial s} (cos (s)) = - sin (s)

= t (- sin (s))

Simplify

= - t sin (s)

\frac{1}{x} y^{^{'}} = \frac{1}{x} - \frac{1}{x ^{3}} - 5 - y

\int \frac{1}{w ^{2} + 9} d w

\frac{d}{d x} (5 - 4 x)

\frac{d}{d x} (x^{2} - 3 x + 2)

\int 2 cos (x) cos^{5} (sin (x)) d x

What is (\partial)/(\partial s)(tcos(s)) ?
The answer to (\partial)/(\partial s)(tcos(s)) is -tsin(s)