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Popular >

(xy^')/(e^y+1)=2

Solution

\frac{x y ^{^{'}}}{e ^{y} + 1} = 2

Solution

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

Solution steps

\frac{x y ^{'} ( x )}{e ^{y} + 1} = 2

Solve linear ODE:

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

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\frac{d}{d x} (- 2 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}}))

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\frac{d}{d x} (r (x) cos^{2} (r (x) x))

integral of e^{8x}cos(9x)

\int e^{8 x} cos (9 x) d x

Frequently Asked Questions (FAQ)

What is the solution for (xy^')/(e^y+1)=2 ?
The solution for (xy^')/(e^y+1)=2 is y=ln(-(x^2)/(x^2-c_{1)})