Solution
Solution
Solution steps
Treat as a constant
Take the constant out:
Apply exponent rule:
Apply the chain rule
Simplify
Popular Examples
16y^{''}+8y^'+y=x+6(dy)/(dx)=((xy+3x-y-3)/(xy-2x+4y-8))y(x+5)+y^'=0sum from n=1 to infinity of (x^n)/(n^n)limit as x approaches 0 of-(1/x)
Frequently Asked Questions (FAQ)
What is (\partial)/(\partial y)((2x)/(x^2+y)) ?
The answer to (\partial)/(\partial y)((2x)/(x^2+y)) is -(2x)/((x^2+y)^2)