What is the tangent of f(x)= 1/(x^5),(1,1) ?

The tangent of f(x)= 1/(x^5),(1,1) is y=-5x+6

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tangent of f(x)= 1/(x^5),(1,1)

tangent of

f (x) = \frac{1}{x ^{5}}, (1, 1)

y = - 5 x + 6

Solution steps

Find the slope of

f (x) = \frac{1}{x ^{5}} : \frac{df ( x )}{d x} = - \frac{5}{x ^{6}}

Compute the slope of

f (x) = \frac{1}{x ^{5}}

(1, 1) : m = - 5

Find the line with slope m=

- 5

and passing through

(1, 1) : y = - 5 x + 6

y = - 5 x + 6

\int_{0}^{1} 1 + 81 x d x

x \to 3 lim (lo g_{3} (2 x^{3}))

\int x^{2} - 2 x^{4} d x

n = 0 \sum \infty \frac{2}{e ^{n}}

\frac{\partial}{\partial x} (sin (3 x - 4 y))

What is the tangent of f(x)= 1/(x^5),(1,1) ?
The tangent of f(x)= 1/(x^5),(1,1) is y=-5x+6