What is the sum from n=1 to infinity of 6/(pi*n) ?

The sum from n=1 to infinity of 6/(pi*n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 6/(pi*n)

n = 1 \sum \infty \frac{6}{π \cdot n}

diverges

Solution steps

n = 1 \sum \infty \frac{6}{πn}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{6}{π} \cdot n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= \frac{6}{π} diverges

= diverges

\int x^{- \frac{3}{4}} + 4 e^{x} d x

\frac{d}{d x} (156 - \frac{x ^{2}}{39})

x \to \infty lim (x^{6})

What is the sum from n=1 to infinity of 6/(pi*n) ?
The sum from n=1 to infinity of 6/(pi*n) is diverges