What is (\partial)/(\partial x)(-x^3y^2) ?

The answer to (\partial)/(\partial x)(-x^3y^2) is -3x^2y^2

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(\partial)/(\partial x)(-x^3y^2)

\frac{\partial}{\partial x} (- x^{3} y^{2})

- 3 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (- x^{3} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - y^{2} \cdot 3 x^{3 - 1}

Simplify

= - 3 x^{2} y^{2}

\int sin^{3} (20 x) d x

x \to 0 + lim (x^{14 x})

\frac{d}{d t} (- 12 cos^{2} (t) sin (t))

\frac{d}{d x} (7 x^{5} + \frac{3 cos ( x )}{x})

\frac{d}{d x} (50 e^{- 0.5 x - \frac{5}{x}})

What is (\partial)/(\partial x)(-x^3y^2) ?
The answer to (\partial)/(\partial x)(-x^3y^2) is -3x^2y^2