What is (\partial)/(\partial y)(y(1-x^2)) ?

The answer to (\partial)/(\partial y)(y(1-x^2)) is 1-x^2

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(\partial)/(\partial y)(y(1-x^2))

\frac{\partial}{\partial y} (y (1 - x^{2}))

1 - x^{2}

Solution steps

\frac{\partial}{\partial y} (y (1 - x^{2}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1 - x^{2}) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= (1 - x^{2}) \cdot 1

Simplify

= 1 - x^{2}

x \to 1 lim (\frac{2 x + 3}{x + 1})

\frac{\partial}{\partial y} (166 x + 456 y - \frac{5000}{x} - \frac{1080}{y} + 43590)

\int 6 x csc (6 x) cot (6 x) d x

f (x) = \frac{64}{x ^{2} + 16}, at x = - 4

5 e^{- t}

What is (\partial)/(\partial y)(y(1-x^2)) ?
The answer to (\partial)/(\partial y)(y(1-x^2)) is 1-x^2