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Popular >

area y=2x,y=5x^2

Solution

area

y = 2 x, y = 5 x^{2}

Solution

\frac{4}{75}

+1

Decimal Notation

0.05333 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{2}{5}} 2 x - 5 x^{2} d x

Solve

\int_{0}^{\frac{2}{5}} 2 x - 5 x^{2} d x : \frac{4}{75}

The area is:

= \frac{4}{75}

Popular Examples

integral of (-4x)

\int (- 4 x) d x

limit as x approaches-6+of (x+5)/(x+6)

x \to - 6 + lim (\frac{x + 5}{x + 6})

integral of (x^4)/4*1/x

\int \frac{x ^{4}}{4} \cdot \frac{1}{x} d x

y^'=t^2e^{-4t}-4y

y^{^{'}} = t^{2} e^{- 4 t} - 4 y

tangent of f(x)=4x(x^2-4x+5)^7,\at x=2 tangent of

f (x) = 4 x (x^{2} - 4 x + 5)^{7}, at x = 2

Frequently Asked Questions (FAQ)

What is area y=2x,y=5x^2 ?
The answer to area y=2x,y=5x^2 is 4/75