What is the solution for (2x^2-ye^x)dx-e^xdy=0 ?

The solution for (2x^2-ye^x)dx-e^xdy=0 is y=(2x^3)/(3e^x)+(c_{1})/(e^x)

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(2x^2-ye^x)dx-e^xdy=0

(2 x^{2} - y e^{x}) d x - e^{x} d y = 0

y = \frac{2 x ^{3}}{3 e ^{x}} + \frac{c _{1}}{e ^{x}}

Solution steps

(2 x^{2} - y e^{x}) d x - e^{x} d y = 0

Solve linear ODE:

y = \frac{2 x ^{3}}{3 e ^{x}} + \frac{c _{1}}{e ^{x}}

y = \frac{2 x ^{3}}{3 e ^{x}} + \frac{c _{1}}{e ^{x}}

\int \frac{ln ( t )}{t} d t

\frac{d}{d x} ((1 + e^{x})^{- 2})

\frac{d}{d x} (x^{3} + 10 x^{2} + 25 x)

\int_{0}^{1} \frac{x}{4 - x ^{2}} d x

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 5 y = 0

What is the solution for (2x^2-ye^x)dx-e^xdy=0 ?
The solution for (2x^2-ye^x)dx-e^xdy=0 is y=(2x^3)/(3e^x)+(c_{1})/(e^x)