What is the derivative of y=220+65x ?

The derivative of y=220+65x is 65

What is the first derivative of y=220+65x ?

The first derivative of y=220+65x is 65

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derivative of

y = 220 + 65 x

65

Solution steps

\frac{d}{d x} (220 + 65 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (220) + \frac{d}{d x} (65 x)

\frac{d}{d x} (220) = 0

\frac{d}{d x} (65 x) = 65

= 0 + 65

Simplify

= 65

f (x) = \frac{x}{x + 8}

(15 x y^{2} - 4 y) + (15 x^{2} y - 4 x) y^{^{'}} = 0

n = 1 \sum \infty \frac{1}{2 ^{n} - 1}

\frac{d}{d t} (- \frac{1}{2 ( t + 1 ) \frac{3}{2}})

x \to - 2 + lim (\frac{3 x - 6}{x + 2})

What is the derivative of y=220+65x ?
The derivative of y=220+65x is 65
What is the first derivative of y=220+65x ?
The first derivative of y=220+65x is 65