What is the derivative of acos(x-pi/2+b) ?

The derivative of acos(x-pi/2+b) is acos(x)

What is the first derivative of acos(x-pi/2+b) ?

The first derivative of acos(x-pi/2+b) is acos(x)

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\frac{d}{d x} (a cos (x - \frac{π}{2}) + b)

a cos (x)

Solution steps

\frac{d}{d x} (a cos (x - \frac{π}{2}) + b)

Simplify

a cos (x - \frac{π}{2}) + b : a sin (x) + b

= \frac{d}{d x} (a sin (x) + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a sin (x)) + \frac{d b}{d x}

\frac{d}{d x} (a sin (x)) = a cos (x)

\frac{d b}{d x} = 0

= a cos (x) + 0

Simplify

= a cos (x)

\int e^{- t (s + 5)} d t

e^{2 x}, 2

\frac{\partial}{\partial z} (e^{x y} ln (z))

f (x) = 2 x^{3} + 5 x^{2}, at x = - 2

\frac{d}{d x} (\frac{a x + 1 + x}{x ^{2} - 1})

What is the derivative of acos(x-pi/2+b) ?
The derivative of acos(x-pi/2+b) is acos(x)
What is the first derivative of acos(x-pi/2+b) ?
The first derivative of acos(x-pi/2+b) is acos(x)