What is the solution for (dy)/(cos(x)+y)=dx ?

The solution for (dy)/(cos(x)+y)=dx is y=(sin(x))/2-(cos(x))/2+c_{1}e^x

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(dy)/(cos(x)+y)=dx

\frac{d y}{cos ( x ) + y} = d x

y = \frac{sin ( x )}{2} - \frac{cos ( x )}{2} + c_{1} e^{x}

Solution steps

\frac{d y}{cos ( x ) + y} = d x

Solve linear ODE:

y = \frac{sin ( x )}{2} - \frac{cos ( x )}{2} + c_{1} e^{x}

y = \frac{sin ( x )}{2} - \frac{cos ( x )}{2} + c_{1} e^{x}

\int_{0}^{1} sin^{2} (π x) d x

\frac{\partial}{\partial x} (arctan (x + 2 y))

\int \frac{1}{x} ln (x^{2}) d x

x \to 18 lim (\frac{1}{x - 18})

x \to 1 lim (f (x) (5 - x))

What is the solution for (dy)/(cos(x)+y)=dx ?
The solution for (dy)/(cos(x)+y)=dx is y=(sin(x))/2-(cos(x))/2+c_{1}e^x