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Popular >

y^'+a*y=b

Solution

y^{^{'}} + a \cdot y = b

Solution

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Solution steps

y^{'} (t) + a \cdot y = b

Solve separable ODE:

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Popular Examples

derivative of 2x+2(cos(x+1)sin(x))

\frac{d}{d x} (2 x + 2 (cos (x) + 1) sin (x))

integral of sec^6(3x)tan^2(3x)

\int sec^{6} (3 x) tan^{2} (3 x) d x

derivative of f(x)=(1+4x)/(9-6x)derivative of

f (x) = \frac{1 + 4 x}{9 - 6 x}

integral of-x^2+5x

\int - x^{2} + 5 x d x

(\partial)/(\partial x)((3y-6x)/(y^2+7x^2))

\frac{\partial}{\partial x} (\frac{3 y - 6 x}{y ^{2} + 7 x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'+a*y=b ?
The solution for y^'+a*y=b is y=-(e^{-at-c_{1}a})/a+b/a