What is the limit as x approaches 8 of 1+\sqrt[3]{x} ?

The limit as x approaches 8 of 1+\sqrt[3]{x} is 3

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limit as x approaches 8 of 1+\sqrt[3]{x}

x \to 8 lim (1 + 3 x)

3

Solution steps

x \to 8 lim (1 + 3 x)

Plug in the value

x = 8

= 1 + 38

Simplify

1 + 38 : 3

= 3

x^{2} y^{^{'}} - x (x + 2) y = e^{x}

ln (t^{2} + 1)

x \to 0 lim (\frac{x ^{3}}{x})

\int \frac{2 x ^{4} + 7 x ^{3} - x}{x ^{3}} d x

\frac{\partial}{\partial t} (x e^{2 t} - 4 x)

What is the limit as x approaches 8 of 1+\sqrt[3]{x} ?
The limit as x approaches 8 of 1+\sqrt[3]{x} is 3