What is the sum from n=0 to infinity of e^{-n/2} ?

The sum from n=0 to infinity of e^{-n/2} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of e^{-n/2}

n = 0 \sum \infty e^{- \frac{n}{2}}

converges

Solution steps

n = 0 \sum \infty e^{- \frac{n}{2}}

Apply Series Ratio Test:

converges

= converges

x + y^{2} = 4, x + y = 2

\frac{d}{d x} (uv w z (u, v, w, x))

x \to 3 - lim (x - 1)

x \to - 1 lim (6 x + 1)

\frac{\partial}{\partial x} (3 (y^{2} - x^{2}) ln (x + y))

What is the sum from n=0 to infinity of e^{-n/2} ?
The sum from n=0 to infinity of e^{-n/2} is converges