What is the derivative of ce^{-3x} ?

The derivative of ce^{-3x} is -3ce^{-3x}

What is the first derivative of ce^{-3x} ?

The first derivative of ce^{-3x} is -3ce^{-3x}

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\frac{d}{d x} (c e^{- 3 x})

- 3 c e^{- 3 x}

Solution steps

\frac{d}{d x} (c e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= c e^{- 3 x} (- 3)

Simplify

= - 3 c e^{- 3 x}

f (x) = \frac{120 x ^{2}}{x ^{2} + 4}

\frac{d}{d x} (ln ∣ x + 2 ∣)

y^{^{'}} = \frac{y ^{2} + 1}{x ^{2} + 1}, y (0) = 1

\frac{d y}{d t} = a y

x \to 0 lim (\frac{tan ( 12 x )}{sin ( 3 x )})

What is the derivative of ce^{-3x} ?
The derivative of ce^{-3x} is -3ce^{-3x}
What is the first derivative of ce^{-3x} ?
The first derivative of ce^{-3x} is -3ce^{-3x}