What is the derivative of x^2+8x+7 ?

The derivative of x^2+8x+7 is 2x+8

What is the first derivative of x^2+8x+7 ?

The first derivative of x^2+8x+7 is 2x+8

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\frac{d}{d x} (x^{2} + 8 x + 7)

2 x + 8

Solution steps

\frac{d}{d x} (x^{2} + 8 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (7) = 0

= 2 x + 8 + 0

Simplify

= 2 x + 8

y = x, y = 2 x - 15, y = 0

5 \frac{d v}{d t} = 49.05 - 50 v

y = \frac{1}{2} x^{2} + 2 x + 3

\frac{x - 15}{x - 15}

x \to 0 lim (\frac{x}{sin ( x ^{2} )})

What is the derivative of x^2+8x+7 ?
The derivative of x^2+8x+7 is 2x+8
What is the first derivative of x^2+8x+7 ?
The first derivative of x^2+8x+7 is 2x+8