What is the integral from 1 to infinity of 1/(5x+2) ?

The integral from 1 to infinity of 1/(5x+2) is diverges

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integral from 1 to infinity of 1/(5x+2)

\int_{1}^{\infty} \frac{1}{5 x + 2} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{5 x + 2} d x

Compute the indefinite integral:

\int \frac{1}{5 x + 2} d x = \frac{1}{5} ln ∣ 5 x + 2 ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{5 x + 2} d x =

diverges

= diverges

\frac{d}{d x} (lo g_{7} (x^{2}))

\frac{d}{d x} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})

\frac{d}{d x} (6 (2 x - 9)^{5})

(5 x + y e^{(\frac{y}{x})}) d x - x e^{\frac{y}{x}} d y = 0

\frac{\partial}{\partial x} (ln (cos (x y) + 2))

What is the integral from 1 to infinity of 1/(5x+2) ?
The integral from 1 to infinity of 1/(5x+2) is diverges