What is the derivative of 3x^4+15 ?

The derivative of 3x^4+15 is 12x^3

What is the first derivative of 3x^4+15 ?

The first derivative of 3x^4+15 is 12x^3

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\frac{d}{d x} (3 x^{4} + 15)

12 x^{3}

Solution steps

\frac{d}{d x} (3 x^{4} + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (15)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (15) = 0

= 12 x^{3} + 0

Simplify

= 12 x^{3}

e^{6 x} cos (9 x)

y = \frac{4}{x}, (- 4, - 1)

\int \frac{- x ^{6} - x ^{4} + x ^{2} + 6}{x ^{2} + 1} d x

\frac{\partial}{\partial x} (x^{5} + 4 z^{2} e^{y - x})

\int x^{3} e^{- \frac{x}{3}} d x

What is the derivative of 3x^4+15 ?
The derivative of 3x^4+15 is 12x^3
What is the first derivative of 3x^4+15 ?
The first derivative of 3x^4+15 is 12x^3