What is the derivative of-3x^{1/2} ?

The derivative of-3x^{1/2} is -3/(2x^{1/2)}

What is the first derivative of-3x^{1/2} ?

The first derivative of-3x^{1/2} is -3/(2x^{1/2)}

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\frac{d}{d x} (- 3 x^{\frac{1}{2}})

- \frac{3}{2 x ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} (- 3 x^{\frac{1}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 \cdot \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

- 3 \cdot \frac{1}{2} x^{\frac{1}{2} - 1} : - \frac{3}{2 x ^{\frac{1}{2}}}

= - \frac{3}{2 x ^{\frac{1}{2}}}

\int \frac{3 x}{x ^{2} - 1} d x

\int 2 x x + 2 d x

y^{^{''}} - 22 y^{^{'}} + 121 y = 0

n \to \infty lim (i = 1 \sum n \frac{1}{2 n + i})

\frac{\partial}{\partial x} (5 x^{2} y^{3} + 2 x^{2} + 7 y)

What is the derivative of-3x^{1/2} ?
The derivative of-3x^{1/2} is -3/(2x^{1/2)}
What is the first derivative of-3x^{1/2} ?
The first derivative of-3x^{1/2} is -3/(2x^{1/2)}