What is the derivative of x^3+e^x ?

The derivative of x^3+e^x is 3x^2+e^x

What is the first derivative of x^3+e^x ?

The first derivative of x^3+e^x is 3x^2+e^x

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derivative of

x^{3} + e^{x}

3 x^{2} + e^{x}

Solution steps

\frac{d}{d x} (x^{3} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 3 x^{2} + e^{x}

\int 9 + t^{2} d t

\frac{d y}{d x} = \frac{y}{x} + \frac{9 x ^{2}}{y ^{2}}

\int \frac{12 x ^{2}}{4 x ^{3} + 1} d x

\int \frac{2 x - 5}{x ^{2} - 5 x + 6} d x

\int_{12}^{\infty} x e^{- x} d x

What is the derivative of x^3+e^x ?
The derivative of x^3+e^x is 3x^2+e^x
What is the first derivative of x^3+e^x ?
The first derivative of x^3+e^x is 3x^2+e^x